Puzzle 15 : All but two
Solution to puzzle 14
Huh, sending more money would have been much easier than this puzzle.
SEND
MORE
MONEY
We have to find values for S,E,N,D,M,O,R,Y (8 digits out of 10).
Now, we're adding two 4-digits numbers.
Since 9999+9999 < 20000, M cannot be >=2.And by the "usual rules" for this kind of question, it can't be 0. So M=1.
Now, looking at the fourth (left-most) column, we have either S+1>=10 (if there's no carry) or 1+S+1>=10 (if there's carry). So S=8 or 9, and O=0 or 1. Since 1 is already taken, O=0
In the third column, we can't have E+0=N (no carry), so E+1=N and there's carry from the second column.
So in the second column either N+R=10+E=9+N, and R=9, or there's carry and 1+N+R=10+E=9+N, and R=8. So R=8 or 9, just like S.
IF S=8 and R=9,we're looking at
But this cannot possibly work: we need to get either E+0=10+N or 1+E+0=10+N in the third column, to get carry in the fourth column. Neither is possible (we've already used up both 9 and 0). So...8END + 109E ====== 10NEY
S=9 and R=8.
We're looking at
We've already used up the digits 0,1,8,9, and N=E+1, so the only choices for E are 6,5,4,3,2.9END + 108E ====== 10NEY
We know we must have carry from the first column into the second, so D+E>=10. D is at most 7, so we immediately rule out E=2 (7+2<10). Also E=3 is impossible (because then either D=7 and Y=0=O, or D<7 and E+D<10, both of which are impossible).
If E=4, then D=7 or D=6 don't work (because then Y=1 or Y=0, and both are already taken), and D<6 doesn't work because then E+D<10.
If E=6 then N=7, so D<=5. But D=5 yields Y=1 and D=4 yields Y=0, both taken, and D<=3 gives E+D<10.
So E=5 and N=6. D=7 (the alternative, D<=4, is again too small), so Y=2 and the solution is
9567 + 1085 ====== 10652
I have borrowed this solution from https://everything2.com/title/send+more+money+solution
Thank you everything.
Puzzle 15 : All but two
I have borrowed this puzzle from genius puzzles website.
I was invited to a pet show by a colleague. Since I was a bit
busy that day, I sent my brother to the show. When he returned back I
asked him about the show. He told me that all except two animals were
fishes, all except two animals were cats and all except two entries were
dogs.
Can you tell me how many
animals of each kind were present in that pet show?
Bonus
The question states that you have to form all the numbers from 1 to 100 using the digits of the year 2020 and the mathematical operators + - X / ! !! () and sqrt and ^. All the digits have to be used. I know few of you are jumping up from excitation.
e.g.
1 = 2/2 + 0+0
2 = 2 - 2 + 0!+ 0!
3 = 2^2 - 0! + 0
4 = 2+2+0+0
5 = 2+2+0!+0
and so on.
This is the website and where you can send solution .
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