Puzzle 110 - Solution
Answer : 4 units
Area of a hexagon which is inscribed in a circle of radius r is 3 √3 / 2 * r2
This hexagon has its side = radius of circle.
But the circumscribed hexagon has radius of the circle as its perpendicular to a side from center of circle.
As shown in the diagram, if the side of outer hexagon is s, then the radius from center of circle perpendicular to the side, cuts the side in half. So the radius forms a right angled triangle with three sides as r, s/2 and hypotenuse as s.
Using Pythagoras theorem
s2 = r2 +s2 /4
3s2 /4 = r2
s2 =r2 * 4/3
Now replacing this value for the area of outer hexagon, we get
area = 3 √3 / 2 *s2 = 3 √3 / 2* r2 * 4/3
But area of inner hexagon is 3 => 3 √3 / 2* r2 is 3
Area of circumscribed hexagon = 3 * 4/3 = 4 units.
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